请把下面公式编写成通达信选股公式，要求选出四量第一天全红，谢谢

问题补充说明：MID:=(3*CLOSE+LOW+OPEN+HIGH)/6;牛线:=(20*MID+19*REF(MID,1)+18*REF(MID,2)+17*REF(MID,3)+16*REF(MID,4)+15*REF(MID,5)+14*REF(MID,6)+13*REF(MID,7)+12*REF(MID,8)+11*REF(MID,9)... MID:=(3*CLOSE+LOW+OPEN+HIGH)/6;牛线:= (20*MID+19*REF(MID,1)+18*REF(MID,2)+17*REF(MID,3)+16*REF(MID,4)+15*REF(MID,5)+14*REF(MID,6)+13*REF(MID,7)+12*REF(MID,8)+11*REF(MID,9)+10*REF(MID,10)+9*REF(MID,11)+8*REF(MID,12)+7*REF(MID,13)+6*REF(MID,14)+5*REF(MID,15)+4*REF(MID,16)+3*REF(MID,17)+2*REF(MID,18)+REF(MID,20))/210,COLORGREEN{COLORRED};马线:=MA(牛线,6),COLORMAGENTA{COLORYELLOW};STICKLINE(C>牛线,2.5,4,8,0),COLORRED{COLORGREEN},LINETHICK2;STICKLINE(C<马线,2.5,4,8,0),COLORGREEN{COLORRED},LINETHICK2;STICKLINE(牛线>=C AND C>=马线,2.5,4,8,0),COLORGREEN{COLORMAGENTA}{COLORYELLOW},LINETHICK2;A:=MAX(MA(C,60),MA(C,120));B:=MIN(MA(C,60),MA(C,120));STICKLINE(C>=A,0.5,2,8,0),COLORRED{COLORGREEN},LINETHICK2;STICKLINE(C<=B,0.5,2,8,0),COLORGREEN{COLORRED},LINETHICK2;STICKLINE(A>=C AND C>=B,0.5,2,8,0),COLORGREEN{COLORMAGENTA}{COLORYELLOW},LINETHICK2;{R:=0;}E:=MAX(MA(C,45),MA(C,90));F:=MIN(MA(C,45),MA(C,90));STICKLINE(C>E,-1.5,0,8,0),COLORRED{COLORGREEN},LINETHICK2;STICKLINE(C=C AND C>=F,-1.5,0,8,0),COLORGREEN{COLORMAGENTA}{COLORYELLOW},LINETHICK2;J:=MAX(MA(C,30),MA(C,60));K:=MIN(MA(C,30),MA(C,60));STICKLINE(C>J,-3.5,-2,8,0),COLORRED{COLORGREEN},LINETHICK2;STICKLINE(C=C AND C>=K,-3.5,-2,8,0),COLORGREEN{COLORMAGENTA}{COLORYELLOW},LINETHICK2; 展开

MID:=(3*CLOSE+LOW+OPEN+H来自IGH)/6;

牛线360问答:=(20*MID+19*REF(MID,1)+18*节义周REF(MID,2)+17*REF(MID,3)+16*REF(MID,4)+15*REF(MID,5)+14*REF(MID,6)+13*REF(M赶尼ID,7)+12*REF(MID,8)+11*REF(MID,9)+10*REF(M走模苦唱造年己括华住困ID,10)+9*REF(MID,11)+8*REF(MID,12)+7*REF(MID,13)+6*REF(MID,14)+5*REF(MID,15)+4*REF(MID,16)+3*REF(MID,17)+2*RE破重起次F(MID,18)+REF(M年天菜校比联医ID,20))/官浓温出含留喜升灯评210;

马线:=MA(牛线,6);

A:=MAX(M制排冲素称春理坏排战烧A(C,60),杂告菜反马观调肉开MA(C,120));

B:=MIN(MA(C,60),MA(C,120));

E:=MAX(M特A(C,45),MA(C,90));

F:=MIN(MA(C,45),MA(C,90));

J:=MAX(MA(C,30),MA(C,60));

K:=MIN(MA(C,30),MA(C,60));

T1:=CROSS(C,牛线)ANDCROSS(C,A)ANDCROSS(C,E)ANDCROSS(C,J);

T2:=NOT(牛线>=CANDC>=马线)ANDNOT(A>=CANDC>=B)ANDNO真乎T(E>=CANDC>=基太离植应积独质设F)ANDNOT(J>=CANDC>=K);

T3:=NOT(C<马线)ANDNOT(C<=B)ANDNOT(C<F)ANDNOT(C<K);

XG:T1=1ANDT2=1ANDT3=1;